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Is religion dying?

dybmh

ויהי מבדיל בין מים למים
1) { 1,2,3 } =/= { 1,2,3,{} } - Game over

why?

how does that entail that {} is not a subset of {1,2,3}?

Why? Because {} does not behave like any other subset that exists.

{ A } is a subset of { A,B,C }. { 1 } is a subset of { 1,2,3 }.
If {} is a subset of { 1,2,3 } then it should exist between the curly brackets just as all the other examples that exist.
{ 1,2,3,{} } describes {} as a subset like all the other examples of a subset that exist.
{ 1,2,3 } describes something else.
{ 1,2,3 } =/= { 1,2,3,{} } proves that {} is not a subset of any set.

How? That's more complicated. The mechanics of this are complex. One needs to derive {}. Essentially {} is not really a set. It's better described as a class. One can consider it as a set, an empty box, but when that happens, they are actually describing { {} } not {}.
 

dybmh

ויהי מבדיל בין מים למים
What on earth is the opposite of a subset?

Well, it's not "on earth". That's the point. {} is the opposite of all of that. Here is something from Duke university.

In our semantic conceptualization of all things that are, that are minimally in their own identity set, we can ``fill'' the empty set by taking the union of the empty set with a nonempty set. We can consider the intersection of the empty set with any nonempty set and of course get the empty set. However, we cannot take the intersection of all things that belong to no set at all including the empty set with any set. If the result were the empty set, then the set we intersected was not in fact the set of all things not in any set including the empty set. The null set is therefore the absence of any box - it lies outside the algebra of the set where the empty set is within the algebra. Similarly the union of any real set (including the empty set) with the null set is undefined, is itself null.​
Notice: It can be considered... However...

{} union with any set = "cannot be evaluated"

{ {} } union with any set = any set, itself. It's an identity.

{} is not an empty box. An empty box is oblivion. {} is annihilation.

This is the opposite of a subset: { not 1 AND not 2 AND not 3 AND not 4 AND not 5 AND not 6 AND not 7 AND not 8 AND not 9 ... }
Notice: there are no commas, this is not a set. It's not a collection, it is negation. It is not inclusion. It is exclusion. Pure exclusion. True falsehood.

This is derived by taking the union of all disjointed sets.

... { -1 } ∩ { 0 } ∩ { 1 } ∩ { 2 } ∩ { 3 } ∩ { 4 } ∩ { 5 } ∩ { 6 } ∩ { 7 } ∩ { 8 } ... = {} = THE empty set. It is NOT anything and NOT everything.

This is why {} =/= {}. That's because {} is not an "empty box". If it were just an empty box, then {} = {}. But that is false. It's false for the reason I mentioned earlier. The {} indicates exclusion, but the "=" indicates inclusion. {} contradicts with "=". Therefore, it's NOT true. {} =/= {}. That is pure exclusion! And therefore a true statement can be made about {} using negation. {} is neither finite or infinte. It is something else. Literally. It is completely unbounded nothingness.

This is the opposite of a subset:

Screenshot_20230505_081601.jpg


The arrows are pointing to the opposite of a subset. Notice. It just keeps going.
 
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viole

Ontological Naturalist
Premium Member
{ A } is a subset of { A,B,C }. { 1 } is a subset of { 1,2,3 }.
If {} is a subset of { 1,2,3 } then it should exist between the curly brackets just as all the other examples that exist.
Let's follow your criteria to detect subsets.

{A} is a subset of {A, B, C}. Why, then? Because {A} exists between the curly brackets of {A, B, C], as you said?

But {A} does not exist between the curly brackets of {A, B, C}. Where is it? I see an A, but I see no {A}.

Therefore, your criteria of proving subsets fails, and your conclusions are invalid. And your arguments fails.

Easy.

Ciao

- viole
 
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dybmh

ויהי מבדיל בין מים למים
So, what do you think of them also disagreeing with you? Do you now admit that you have been wrong all along?

See below:

Some authors have problems with the existence (or not) of the empty set:

1965: J.A. Green: Sets and Groups: §1.3:
If A,B are disjoint, then A∩B is not really defined, because it has no elements. For this reason we introduce a conventional empty set, denoted ∅, to be thought of as a 'set with no elements'. Of course this is a set only by courtesy, but it is convenient to allow ∅ the status of a set.​

1968: Ian D. Macdonald: The Theory of Groups: Appendix:
The best attitude towards the empty set ∅ is, perhaps, to regard it as an interesting curiosity, a convenient fiction. To say that x∈∅ simply means that x does not exist. Note that it is conveniently agreed that ∅ is a subset of every set, for elements of ∅ are supposed to possess every property.​

2000: James R. Munkres: Topology (2nd ed.): 1: Set Theory and Logic: §1: Fundamental Concepts
Now some students are bothered with the notion of an "empty set". "How", they say, "can you have a set with nothing in it?" ... The empty set is only a convention, and mathematics could very well get along without it. But it is a very convenient convention, for it saves us a good deal of awkwardness in stating theorems and proving them​

In other words, considering {} as a set is an axiom but cannot be proven. It is adopted out of convenience. But if/when this religious-style dogma produces false conclusions, it needs to be re-evaluated.
 

dybmh

ויהי מבדיל בין מים למים
Let's follow your criteria to detect subsets.

{A} is a subset of {A, B, C}. Why, then? Because {A} exists between the curly brackets of {A, B, C], as you said?

But {A} does not exist between the curly brackets of {A, B, C}. Where is it? I see an A, but I see no {A}.

Therefore, your criteria of proving subsets fails, and your conclusions are invalid. And your arguments fails.

Easy.

Ciao

- viole

Following the pattern of all other subsets that exist, a subset describes what is between the curly brackets. "A" is in the curly brackets in { A }, and "A" is in the curly brackets in { A,B,C }. That is true for any subset that exists including { A,B,C,{} }.
 

viole

Ontological Naturalist
Premium Member
Following the pattern of all other subsets that exist, a subset describes what is between the curly brackets. "A" is in the curly brackets in { A }, and "A" is in the curly brackets in { A,B,C }. That is true for any subset that exists including { A,B,C,{} }.
Wait a second. Just be sure.

For you, {A} is a subset of {A,B,C} because what is between the curly brackets of {A}, is also between the curly brackets of {A,B,C}?

Ciao

- viole
 

viole

Ontological Naturalist
Premium Member
In other words, considering {} as a set is an axiom but cannot be proven. It is adopted out of convenience. But if/when this religious-style dogma produces false conclusions, it needs to be re-evaluated.
Well, at present, the only one producing false conclusions, and actually believing them, is you.

Ciao

- viole
 
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dybmh

ויהי מבדיל בין מים למים
Wait a second. Just be sure.

For you, {A} is a subset of {A,B,C} because what is between the curly brackets of {A}, is also between the curly brackets of {A,B,C}?

Ciao

- viole

Yes.
 

dybmh

ויהי מבדיל בין מים למים
Well, at present, the only one producing false conclusions, and actually believing them, is you.

Ciao

- viole

This is a false conclusion. It comes from the children's website you posted previously. Which, ya know, makes sense that it would have something false on it.

Since there are no elements of {} at all, there is no element of {} that is not in A, leading us to conclude that every element of {} is in A and that {} is a subset of A. Any statement that begins "for every element of {}" is not making any substantive claim; it is a vacuous truth. This is often paraphrased as "everything is true of the elements of the empty set."​
Notice. They are taking a state which is pure exclusion, and then flipping it into a statement of partially pure inclusion.

There are NO elements of {} ... exclusion.
There are no elements of {} that is not in A ... exclusion & exclusion
Leads us to conclude that every element of {} is in A ... inclusion & exclusion & inclusion which is CONTRADICTION.

As I have proven, when there is a contradiction the operators MUST be evaluated/understood IN CONTRADICTION. This is well known. -1 + 1 = 0. Every claim has context. Removing that context, removes the meaning of the claim.

A claim which is NOT proven false does not define a true statement. That is the definition of a false conclusion.

If there are no elements that are not in A =/= all of its elements are in A. That is a false conclusion.

If a conclusion is derived from statements that are not contradicting, then it can be understood naturally. If the conclusion is dervied from contradicting statements, then the conclusion needs to be understood in contradiction.

{} is NOT a subset of any set, BECAUSE it is has no elements in any set. Exclusion & exclusion & exclusion. True.
 
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viole

Ontological Naturalist
Premium Member
So, why do you say that {} is not a subset of {1,2,3}, on account of the fact that {1,2,3} is different from {1,2,3,{}}?
Makes no sense. That is non sequitur that contradicts your own definition.

That would be like saying that {1} is not a subset of {1,2,3}, on account of the fact that {1,2,3} is different from {1,2,3,{1}}. Which is of course a wrong conclusion.

Ciao

- viole
 

Zwing

Active Member
**MOD POST**

THIS THREAD IS IN A DISCUSSION AREA OF THE FORUM. ANY DEBATING PAST THIS POINT WILL BE MODERATED UNDER RULE 10 OF THE FORUM RULES.
Is there a debate forum to which this might be moved? I suspect this dialogue has a bit of an audience, of which I am a part.

EDIT: I would suggest moving this to the “Religious Debates” forum, even though the non-religious aspect has become prominent. I suppose that nobody would take exception, especially those of us who have stocked up on chips and dip as they await the next flurry of postings. If this must stop, what am I gonna do with all these chips and dip?
 
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dybmh

ויהי מבדיל בין מים למים
So, why do you say that {} is not a subset of {1,2,3}, on account of the fact that {1,2,3} is different from {1,2,3,{}}?

Because it doesn't behave like any other subset that exists.

Makes no sense. That is non sequitur that contradicts your own definition.

Do pigs have wings? {} is a subset, like pigs have wings. And that is literally true.

That would be like saying that {1} is not a subset of {1,2,3}, on account of the fact that {1,2,3} is different from {1,2,3,{1}}. Which is of course a wrong conclusion.

No, I am saying that { 1 } is a subset of { 1,2,3 } because "1" exists in { 1,2,3 }.
Can you say the same for {}? What are the contents of {}? How do the contents of {} correspond with { 1,2,3 }? I think if you answer these questions honestly and correctly, we will easily see that {} is NOT a subset of { 1,2,3 }, and that is precisely what the following statements mean.

We do not disagree about the facts; we disagree on what those facts mean.

{ 1,2,3 } ∩ { 4,5,6 } = {} = NOT a subset
{ 4,5,6 } ∩ { 7,8,9 } = {} = NOT a subset
{ 7,8,9 } ∩ { A,B,C } = {} = NOT a subset
{ A,B,C } ∩ { D,E,F } = {} = NOT a subset
{ D,E,F } ∩ { G,H,I } = {} = NOT a subset
{ G,H,I } ∩ { J,K,L } = {} = NOT a subset
{ J,K,L } ∩ { M,N,O } = {} = NOT a subset
{ M,N,O } ∩ { P,Q,R } = {} = NOT a subset

When the intersection results in {} that means neither set is a subset.

Assuming that {} is a set then:

{} ∩ { 1,2,3 } = {} = NOT a subset
{} ∩ { 4,5,6 } = {} = NOT a subset
{} ∩ { 7,8,9 } = {} = NOT a subset
{} ∩ { A,B,C } = {} = NOT a subset
{} ∩ { D,E,F } = {} = NOT a subset
{} ∩ { G,H,I } = {} = NOT a subset
{} ∩ { J,K,L } = {} = NOT a subset
{} ∩ { M,N,O } = {} = NOT a subset

If a person makes the mistake of considering {} like a variable in algebra, then they will misunderstand the results of the intersections above.

When an intersection results in {} that MEANS there is no intersection, which means there is no subset.

However! If {} is assumed to be a set, then, there is a commonality. But not correspondence. The commonality is that the intersection is between two sets. In other words the curly brackets match, and nothing else. But that's not a subset. That's just the borders around these theoretical sets.
 
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viole

Ontological Naturalist
Premium Member
Because it doesn't behave like any other subset that exists.
What is a subset that exists? Does your point only refer to subsets of things that actually exist?

And why is not that applicable to the empty set? Empty sets are just sets with no elements. No biggie, really. So, I am not sure why they should be so exotic to deserve special treatment. So, can you tell us how they should behave differently? We need some definitions here, or special cases which are logical viable, beyond the ones we already have, which make my case really, as they make a case for all logicians and mathematicians in the world, so probably you would object on them. So, I am just giving you the chance here to make up your own definitions, and see if they are viable.

Now, you said that {A} is a subset of {A,B,C} because what is between the curly brackets of {A}, is also between the curly brackets of {A,B,C}.
So, if you were coherent, then in order to ascertain whether {} is a subset of {A, B, C}, we should only look at what is between the curly brackets of {}. Don't you think?

At face value, what is between the brackets of {} is nothing. And if I add nothing to {A, B, C}, I obtain again {A, B, C}. Which will indicate that {A, B, C} really already contained that nothing between the curly brackets of {}, since I just added it to it without any effect.

Don't you think? If you do not agree, why don't you agree?

Another question. If I remove 1 and 2 and 3, from {1,2,3}, what do you think I will obtain as resulting set?

Ciao

- viole
 
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viole

Ontological Naturalist
Premium Member
Do pigs have wings? {} is a subset, like pigs have wings. And that is literally true.
Yes, the set of pigs having wings is {}. And that is literally true.

So?

Do you think that the set of pigs with wings has more than zero elements?


Ciao

- viole
 
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Hockeycowboy

Witness for Jehovah
Premium Member
Yes, it is. And from what I’ve been taught regarding Biblical prophecy in Revelation chapters 17 & 18, it will soon be destroyed by the world’s major political element.

The way events are turning out, I can see this happening.
 

viole

Ontological Naturalist
Premium Member
Yes, it is. And from what I’ve been taught regarding Biblical prophecy in Revelation chapters 17 & 18, it will soon be destroyed by the world’s major political element.

The way events are turning out, I can see this happening.
So, thou should be happy that Revelation's prophecy is fulfilled, right?

Ciao

- viole
 

dybmh

ויהי מבדיל בין מים למים
What is a subset that exists? Does your point only refer to subsets of things that actually exist?

Yes, my point is that a subset must exist inorder to be called a subset. If it does not exist, then it cannot be named, quantified, or qualified with any truth. If it does not exist then anything that is said about it is false by definition.

For example, right now, take your hand, open it, shake it out, look at your palm, and make a truthful statement about what you see in your hand.

And why is not that applicable to the empty set?

Because they are opposite. A subset exists and contains. THE empty set does not exist and excludes.

Empty sets are just sets with no elements. No biggie, really. So, I am not sure why they should be so exotic to deserve special treatment.

Because they do not behave like any other set. So it's not so simple. Why is {} =/= {} ? If we're just talking about an empty box, then certainly one empty box is equal to the same empty box? Why is {} = {} false?

So, can you tell us how they should behave differently? We need some definitions here, or special cases which are logical viable, beyond the ones we already have, which make my case really, as they make a case for all logicians and mathematicians in the world, so probably you would object on them. So, I am just giving you the chance here to make up your own definitions, and see if they are viable.

I'm not making up any defintions.

I am using well established defintions:

Screenshot_20230505_152015.jpg


Now, you said that {A} is a subset of {A,B,C} because what is between the curly brackets of {A}, is also between the curly brackets of {A,B,C}.
So, if you were coherent, then in order to ascertain whether {} is a subset of {A, B, C}, we should only look at what is between the curly brackets of {}. Don't you think?

Yes.

At face value, what is between the brackets of {} is nothing.

Face value is not a proper way to evaluate the intersection of disjointed sets.

And if I add nothing to {A, B, C}, I obtain again {A, B, C}.

No. { A,B,C } describes a bucket that is completely full. It is full of { A,B,C } and nothing else. If you add "nothing" to it that becomes { A,B,C,{} }. Adding "nothing" in a set means "making more room" or "emptying". This isn't algebra. Nothing is not the same as Zero.

Which will indicate that {A, B, C} really already contained that nothing between the curly brackets of {}, since I just added it to it without any effect.

see above.

Don't you think? If you do not agree, why don't you agree?

Because {} is not "nothing". It is "negation". It negates anything and everything you can imagine and more.

Another question. If I remove 1 and 2 and 3, from {1,2,3}, what do you think I will obtain as resulting set?

Null. It's not even a set anymore.
 
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dybmh

ויהי מבדיל בין מים למים
Yes, the set of pigs having wings is {}. And that is literally true.

So?

Pigs with wings don't exist, and neither does {}. Since it doesn't exist, it cannot be a subset.

Calling it a subset is a convenient fiction, as I posted earlier.

Do you think that the set of pigs with wings has more than zero elements?

The set of pigs with wings does not exist in any natural way. It only exists as a contradiction which means it doesn't exist at all.
 

viole

Ontological Naturalist
Premium Member
Yes, my point is that a subset must exist inorder to be called a subset. If it does not exist, then it cannot be named, quantified, or qualified with any truth. If it does not exist then anything that is said about it is false by definition.

For example, right now, take your hand, open it, shake it out, look at your palm, and make a truthful statement about what you see in your hand.
So, if I denote with X the set of married bachelors, would you say that such a set exists, although married bachelors cannot possibly exist?

Because they are opposite. A subset exists and contains. THE empty set does not exist and excludes.
What does it mean? Why do you think the empty set does not exist? And what do you mean with "does not exist"? Isn't lack of existence represented as a null set to start with? If I am right and there is no God, isn't that the same as saying that the set of Gods is empty? But if the empty set does not exist, wouldn't that imply that God must exist, since there cannot possibly be a state of affairs without Gods?

Consider again the set of all married bachelors. That is obviously the null set, by definition. But if it that set does not exist, then there is not such a state of affairs without married bachelors. Ergo, married bachelors must exist, because if they did not, then their set would be empty, and since there is no empty set, we come to a contradiction.

And what do you mean with "does not exist and excludes". I cannot imagine anything that does not exist, while doing something like excluding. How can it be?

Therefore your ontological claim is absurd, and for that reason not logically tenable. It would immediately lead to the obvious conclusion that everything exists. Including, say, gods who look like Mariah Carey.

Because they do not behave like any other set. So it's not so simple. Why is {} =/= {} ? If we're just talking about an empty box, then certainly one empty box is equal to the same empty box? Why is {} = {} false?
I think it is very simple, if we just take the empty set at face value. Namely, as a set that has no elements. The rest is just simple logic. I wonder why you get so tangled up by something that have nothing inside. I know a lot of people with that property, lol.

You ask: Why is {} =/= {}?
Is it? What makes you think that the empty set is different from the empty set? How can the empty set be different from itself?

Don't you think that anything is equal to itself?

So, to your question, why is {} = {} false? the answer is simple. It is not false. And I wonder how you can defend the claim that there is at least one thing that is different from itself.

Again, your logic leads to absurdities, and it is therefore not tenable.



'm not making up any defintions.

I am using well established defintions:

Screenshot_20230505_152015.jpg

Yes, but you said {} cannot possibly exist. Which is another way of saying that there is not such a thing as disjoint sets. Because if there were, then their intersection would be not existing. In other words, disjointness cannot possibly exist.

Even worse, you said in previous posts the following:

1) The empty set is disjoint from any other set.
2) A is a subset of B if and only if the intersection of A and B is A (you proposed that as criteria for being a subset)

But if that is the case, then taking any set B, the intersection of B with {} must be {}, because of 1) and your definition of disjoint here, which would entail that {} is a subset of B, because of 2). And given the arbitrary choice of B, that will entail that {} is a subset of B, for any B.

Which negates what you have been claiming from the beginning.

this clearly shows that your reasoning is self contradictory, and therefore logically untenable, again.

Cool, so what is between the curly brackets of {}?

Face value is not a proper way to evaluate the intersection of disjointed sets.
fair enough. So, what is, in your opinion, between the curly brackets of {}? Nothing, or something? What does your wisdom suggest?

No. { A,B,C } describes a bucket that is completely full. It is full of { A,B,C } and nothing else. If you add "nothing" to it that becomes { A,B,C,{} }. Adding "nothing" in a set means "making more room" or "emptying". This isn't algebra. Nothing is not the same as Zero.

Nope. if I add X to {A,B,C} and that turns it into {A,B,C,{}}, then I did not add nothing. I added {}. Which is not nothing. It is a set containing nothing. Two different things. I am sure you also agree that a box containing nothing is different from nothing.

Therefore, your argument suffers from a category error (equivocation of nothing with a container containing nothing), and it is therefore not logically tenable. Again, unfortunately.


Null. It's not even a set anymore.

So, if I remove all the balls from a box, then the box is not a box anymore?

Again, your argument suffers from a pathological logical fallacy, in this case the fallacy that containers cease to be containers if what it is contained in them is removed. Which is obviously untenable.

And, again, that leads to the conclusion that your arguments are fatally flawed, all of them, and serve therefore no purpose whatsoever in establishing truth values in statements involving empty sets. Or any other set.

QED

Tschüß

- viole
 
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Hockeycowboy

Witness for Jehovah
Premium Member
So, thou should be happy that Revelation's prophecy is fulfilled, right?

Ciao

- viole
In a way, yes! Religious indoctrination & fervor has been a bane to mankind, killing each other, alienating them from Jehovah our Creator. Very few humans, in comparison to the entire world population, have come to know & worshipped Him.

But all will be given an opportunity, when they are brought back to life in the Resurrection. Acts 24:15.

No more confusion and bad or deceitful influences!

Ciao
 
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