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Riemann Hypothesis. A clear proof.

questfortruth

Well-Known Member
There is a Riemann Zeta function: Zeta(s). The first trillions of zeros of this function Zeta(s)=0 have a real part equal to half: Re s = 1/2. Already from the original work of Prof. Riemann, one knows that if there is a counterexample that does not lie on the critical line Re s = 1/2, then there must be a counterexample symmetric to it: Re s_1=1/2-v, Re s_2=1/2+v. In this case, Zeta(s_1)=Zeta(s_2)=0. Let s_1 and s_2 be unknown positions now. Let's find a system of equations that produces zeros of the Zeta function. Obviously, this is Zeta(s_1)=Zeta(s_2), A(s_1)Zeta(s_1)=A(s_2)Zeta(s_2), where A(s) is an arbitrary function. At a certain A(s), A(s_1)Zeta(s_1)=A(s_2)Zeta(s_2) is automatically executed. Then any solution Zeta(s_1)=Zeta(s_2) is a zero of the Zeta function. Now, repeating the line of reasoning, but with the function B(s)Zeta(s), where B(s) is arbitrary, we come to the conclusion that any solution B(s_1)Zeta(s_1)=B(s_2)Zeta(s_2 ), and not Zeta(s_1)=Zeta(s_2), is the zero of the Zeta function. Contradiction.

The problem will be following, if s_1 is not s_2, the B(s_1)Zeta(s_1)=B(s_2)Zeta(s_2)= is not zero,
will hold; which is not possible because B(s_1)Zeta(s_1)=B(s_2)Zeta(s_2) has to give
the zero of the Zeta function.

Preprint: https://vixra.org/abs/2406.0033
 
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