Japanese IQ test

[michel]

I couldn't even remember half the rules; to get that in my head would take at least a day............besides, I am now at a stage in life when I can afford to say "I am sure I would be lousy at that, I'd rather not know just how lousy"................

 

[MysticSang'ha]

It took me between 8-10 minutes. But the funny part was when I thought I'd do it again, my mind went absolutely blank, and I couldn't remember how I solved it!




So, it took me another 5 minutes to find out again.





I'd seen the same kind of problem in other "tests" before. I like these kinds of mindbenders. Thanks SL!





Peace,
Mystic

 

[Mister Emu]

1 - 2
1
5 - 10
2
1- 2

They get across the bridge just as the police arrive! Run escapees run!

 

[SoyLeche]

1 - 2
1
5 - 10
2
1- 2

They get across the bridge just as the police arrive! Run escapees run!

Frubals to you!

 

[Feathers in Hair]

I loved that! (Though I was alarmed that the robber bears a bit of resemblence to myself! )

 

[Opethian]

Grr why didn't I see this thread before, I wanted those frubals !!!
I bet you can even solve stuff like this with differention equations. (or however 'differentie' from dutch is called in english).

 

[SoyLeche]

Grr why didn't I see this thread before, I wanted those frubals !!!
I bet you can even solve stuff like this with differention equations. (or however 'differentie' from dutch is called in english).

Differential - but you were close Frubals to you anyway!

 

[Opethian]

Thanks! Differential equations is something else than what I was looking for, in dutch they're called "differentiaal", but we also have something called "differentie", which is different, and if I would follow my translation senses I'd guess it would be differention in english. But it's probably called something different in english. Last year we used it to solve a puzzle where you have poles with different sized rings, and I'm not sure how it went cause I don't have the exercise anymore but I think it was the intention to get all the rings on the final pole, the biggest rings on the bottom and the smallest on top, and you could only move one ring at a time, only to the adjacent (next pole), and the rings always had to be in order, biggest on the bottom, smallest on top. You then had to do this with as little moves as possible. Now, for 3 rings and 3 poles it's easy and you don't need any math equations, but if you did this for for example 99 poles and 99 rings, it becomes impossible to do without the equations. I guess stuff like this could also be able to be used for the problems with the prisoners (imagine solving it for 90 different prisoners without an equation ), since the problem is slightly analog.

 

[Matt88]

Here's another one -- let's see if I can explain it well or not.

4 people escape from prison. They come to an old, rickety bridge across a deep gully. The only way across the gully is to use the bridge. The bridge can only support 2 people at a time. The prisoners have only one flashlight, which they need in order to cross the bridge. Throwing the flashlight back to the other side is out of the question.

Prisoner #1 can get across the bridge in 1 minute
Prisoner #2 can get across the bridge in 2 minutes
Prisoner #3 can get across the bridge in 5 minutes
Prisoner #4 can get across the bridge in 10 minutes

When 2 people are crossing at the same time, they can only go as fast as the slowest of them (i.e. 1 and 4 together take 10 minutes, etc).

They have 17 minutes before the police catch up to them. How do they all get across the bridge.

this is what i thought, prisoner one holds the flashlight and lights the path up so everyone can see, prisoner 4 goes first, followed by 3, than 2 and finally one. doubt i'm right though, i hate word problems.

 

[Bastet]

Here's another one -- let's see if I can explain it well or not.

4 people escape from prison. They come to an old, rickety bridge across a deep gully. The only way across the gully is to use the bridge. The bridge can only support 2 people at a time. The prisoners have only one flashlight, which they need in order to cross the bridge. Throwing the flashlight back to the other side is out of the question.

Prisoner #1 can get across the bridge in 1 minute
Prisoner #2 can get across the bridge in 2 minutes
Prisoner #3 can get across the bridge in 5 minutes
Prisoner #4 can get across the bridge in 10 minutes

When 2 people are crossing at the same time, they can only go as fast as the slowest of them (i.e. 1 and 4 together take 10 minutes, etc).

They have 17 minutes before the police catch up to them. How do they all get across the bridge.

1+ 2 cross (takes 2 mins)
1 goes back with flashlight (1 min)
3 + 4 cross (takes 10 mins)
2 goes back with flashlight (2 mins)
1 + 2 cross (2 mins)

2+1+10+2+2 = 17

:woohoo:

Oh, I worked out the OP too. :highfive: These kinds of puzzles drive me nuts.

*edit* I just realised Mr Emu solved it, but I didn't understand his post at all on first glance. :biglaugh:

 

[Bastet]

I loved that! (Though I was alarmed that the robber bears a bit of resemblence to myself! )

Rubbish - there was no tuna!! :tuna: She had a mean kick on her, though.

 

[Shadow Wolf]

Didn't even take five minutes.

I have heard that Microsoft supposedly uses a similiar thing, only using U2 members, time before a show, a flashlight, and a bridge, to help find new employees.

 

[Krie]

im stumped

 

[Bastet]

im stumped

Would it help you to know that one pair cross the river several times, and that the robber can be left on her own - without the policeman?

 

[Runt]

Okay... starting... NOW!

 

[Runt]

Done... NOW!!! (I made 2 mistakes)

That was fun... let's do another!