Yerda
Veteran Member
Hadrons. I think the same quantum weirdness applies though.I'm just curious... If this is the case and photons don't exist, then what are they actually "colliding" with the Large Hadron Collider?
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Hadrons. I think the same quantum weirdness applies though.I'm just curious... If this is the case and photons don't exist, then what are they actually "colliding" with the Large Hadron Collider?
Hadrons. I think the same quantum weirdness applies though.
I think so, yes.But a proton is a hadron, is it not?
I think so, yes.
The problem is one of language, and one I blame on the developers of modern physics from Planck, Einstein, Lorentz, Born, Bohr, von Neumann, Heisenberg, Schrödinger, etc., to Dirac, Pauli, Gell-Mann, Bohm, Fermi, Wigner, etc. Essentially, the language from classical physics continued to be used, only it was used to refer to fundamentally different phenomena (or even non-phenomena). Photons were the original quanta, singular "quantum". Einstein won the Nobel prize for demonstrating that positing light comes in discrete "packets" explained why, when light was shined on metals, upping the intensity only resulted in a "stepwise" increase in the number of electrons that were "knocked out" by the light. Put differently, if light were a wave, then it would be some spread-out, nonlocal "thing" which, if you changed its wavelength or frequency, should change continuously and its effect on e.g., electrons should too. It turns out that when you change the intensity (I'm using this term informally) of light, it won't necessarily mean more or less electrons get knocked out, which for a wave is not just weird, but wrong. However, if you imagine a wave of light as composed of enormous numbers of discrete "packets" or quanta, as Einstein did, you can explain this effect (the photoelectric effect) by assuming Planck's "hail mary" constant as a constant with which the frequency of light must be multiplied in order to give the "energy". Put differently and simplistically, the "energy" of a light beam doesn't change like a wave but makes discrete "jumps", and thus changing intensity is really changing the number of "packets" sufficient to knock electrons out of orbit.I'm just curious... If this is the case and photons don't exist, then what are they actually "colliding" with the Large Hadron Collider?