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I challenge the world , bring it on!

Axe Elf

Prophet
Yep, the formula, for those that care is theta= 1.22*lambda/D . Where theta is the minimum angle of resolution, lambda is the wavelength of light and D is the diameter of the telescope. That also explains why huge telescopes are preferred by astronomers.

Ok, let's see how well you understand what you Googled:

What, pray tell, is the wavelength of light?
 

james blunt

Well-Known Member
Yes please.

Will you lock yourself in the cellar? I can help with that.


Ok, you are in a cellar with the light turned on but all windows and doors prepared for a blackout.

Notice the walls are illuminated , notice the space between your eyes and walls is not light or dark, it is transparent.

Now turn the light off, notice the wall is now its original colour and the space as not changed in appearance.

Now I know you think you just can't see, as if blind, but I assure you , you can and are seeing just fine.

Now shine a laser at the wall, you will not see a beam but you will see the dot on the wall that shows you that you can still see through the space , the space is not dark or opaque.
 

james blunt

Well-Known Member
Doesn't remotely address my question. Care to try again?
yes it does, think about it for a while.

Try this, place a sealed empty box in front of you, move the box to the right, it is now a new space inside the box. The space passes through the box.
 

Subduction Zone

Veteran Member
Ok, let's see how well you understand what you Googled:

What, pray tell, is the wavelength of light?


It varies. Are you talking about visible light? That goes from very roughly 400 to 700 nanometers. Of course if one had x-rays or even gamma-rays the resolution would be finer, but I do not know of too many telescopes that use those frequencies. With radio waves the resolution is less, but we have some HUGE radio telescopes. But I don't know how much light comes from the Moon in the source of radio waves.

Good enough?
 

Axe Elf

Prophet
Ok, you are in a cellar with the light turned on but all windows and doors prepared for a blackout.

Notice the walls are illuminated , notice the space between your eyes and walls is not light or dark, it is transparent.

Now turn the light off, notice the wall is now its original colour and the space as not changed in appearance.

Now I know you think you just can't see, as if blind, but I assure you , you can and are seeing just fine.

Now shine a laser at the wall, you will not see a beam but you will see the dot on the wall that shows you that you can still see though the space , the space is not dark or opaque.

Which part of this figure is lighter, and which part is darker?

Illusion 16.jpg


If you put your finger across the borderline between the two areas, you will get the answer.
 

Drizzt Do'Urden

Deistic Drow Elf
Yep, the formula, for those that care is theta= 1.22*lambda/D . Where theta is the minimum angle of resolution, lambda is the wavelength of light and D is the diameter of the telescope. That also explains why huge telescopes are preferred by astronomers.



Angular resolution - Wikipedia

I owned a Celestron CPC 1100 for years and enjoyed it to no end. Had computerized and motorized go to tech built into it. Once you calibrated it with GPS you could say, if Jupiter was above the horizon at the time, tell it to show you Jupiter and it would track and hold it in view based on your GPS location on the planet. Had lots of fun taking pics of the craters in the moon, Jupiter, Saturn, and several galactic level objects.

Sold it a few years ago for about 80% of what I paid for it. I could also hook my laptop up to it and use a program called Starry Nights to control the telescope.

I still own a 60mm Solar scope and used it last year up in Carbondale Illinois to view the solar eclipse. Drove all the way from Texas to see it. Original destination was Kansas City but weather started pushing us east. Ended up in Carbondal Illinois.

What an awesome day that was! If you've never seen one before, I suggest you do so before you die. Here's a shot from my Nikon D90.
 

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Subduction Zone

Veteran Member
Ok, you are in a cellar with the light turned on but all windows and doors prepared for a blackout.

Notice the walls are illuminated , notice the space between your eyes and walls is not light or dark, it is transparent.

Now turn the light off, notice the wall is now its original colour and the space as not changed in appearance.

Now I know you think you just can't see, as if blind, but I assure you , you can and are seeing just fine.

Now shine a laser at the wall, you will not see a beam but you will see the dot on the wall that shows you that you can still see though the space , the space is not dark or opaque.
More nonsense. Why did I even ask?
 

Axe Elf

Prophet
It varies. Are you talking about visible light? That goes from very roughly 400 to 700 nanometers. Of course if one had x-rays or even gamma-rays the resolution would be finer, but I do not know of too many telescopes that use those frequencies. With radio waves the resolution is less, but we have some HUGE radio telescopes. But I don't know how much light comes from the Moon in the source of radio waves.

Good enough?

Heh. I was just wondering if you would notice that you left out the word "the" in the sentence, "lambda is the wavelength of THE light." Not just light in general, but the light that is currently being observed, for which that formula can determine angular resolution.

Minor point, but worth investigating.
 

Subduction Zone

Veteran Member
I owned a Celestron CPC 1100 for years and enjoyed it to no end. Had computerized and motorized go to tech built into it. Once you calibrated it with GPS you could say, if Jupiter was above the horizon at the time, tell it to show you Jupiter and it would track and hold it in view based on your GPS location on the planet. Had lots of fun taking pics of the craters in the moon, Jupiter, Saturn, and several galactic level objects.

Sold it a few years ago for about 80% of what I paid for it. I could also hook my laptop up to it and use a program called Starry Nights to control the telescope.

I still own a 60mm Solar scope and used it last year up in Carbondale Illinois to view the solar eclipse. Drove all the way from Texas to see it. Original destination was Kansas City but weather started pushing us east. Ended up in Carbondal Illinois.

What an awesome day that was! If you've never seen one before, I suggest you do so before you die. Here's a shot from my Nikon D90.
Nice. The eclipse was about 90% where I live. It got cool and eerily quiet even in the middle of a small city.
 

Kangaroo Feathers

Yea, it is written in the Book of Cyril...
yes it does, think about it for a while.

Try this, place a sealed empty box in front of you, move the box to the right, it is now a new space inside the box. The space passes through the box.
That doesn't remotely address my question. How does that demonstrate that a perfect and unchanging vacuum can exist?
 

james blunt

Well-Known Member
I owned a Celestron CPC 1100 for years and enjoyed it to no end. Had computerized and motorized go to tech built into it. Once you calibrated it with GPS you could say, if Jupiter was above the horizon at the time, tell it to show you Jupiter and it would track and hold it in view based on your GPS location on the planet. Had lots of fun taking pics of the craters in the moon, Jupiter, Saturn, and several galactic level objects.

Sold it a few years ago for about 80% of what I paid for it. I could also hook my laptop up to it and use a program called Starry Nights to control the telescope.

I still own a 60mm Solar scope and used it last year up in Carbondale Illinois to view the solar eclipse. Drove all the way from Texas to see it. Original destination was Kansas City but weather started pushing us east. Ended up in Carbondal Illinois.

What an awesome day that was! If you've never seen one before, I suggest you do so before you die. Here's a shot from my Nikon D90.

Not dark in any of your pics.
 

james blunt

Well-Known Member
That doesn't remotely address my question. How does that demonstrate that a perfect and unchanging vacuum can exist?
It demonstrates that space cannot be displaced, it is the static /stationary reference frame. I gave you a box , XYZ , the box although empty contains elements, remove all these elements and what are you left with?
 

Subduction Zone

Veteran Member
Heh. I was just wondering if you would notice that you left out the word "the" in the sentence, "lambda is the wavelength of THE light." Not just light in general, but the light that is currently being observed, for which that formula can determine angular resolution.

Minor point, but worth investigating.
Nit picking but somewhat valid. At any rate give me the distance and the frequency of light involved and the diameter of the telescope and it is just a matter of plugging numbers into the equation. At that small of an angle the sine will be equal to the angle in radians to any reasonable number of significant digits.
 

Drizzt Do'Urden

Deistic Drow Elf
Nice. The eclipse was about 90% where I live. It got cool and eerily quiet even in the middle of a small city.

I live close to Dallas and there is another solar eclipse that will take place in April of 2024. The center line of the shadow passes about 5 miles away from my home so I'm going to have a great view, but the beauty of being right on the centerline is that you get the best view and the longest dark period. Carbondale's total dark time was like 2 minutes 40 seconds long because the eclipse took place in the end of summer/fall. The one in 2024 is in April, thus the total dark time will be more like 5 minutes in length, or pretty close to it.

The length of the totality is prescribed by your location on the planet as well as the time of year (ie tilt of the planet).

It was really a cool experience. It was odd because any direction you looked while it was happening looked like a sunset where the sun is below the horizon already. The air cooled about 10 degrees, the crickets and sundown critters all started chirping, the birds and dogs howling and making noise.

Really an awesome thing to witness...

My plan in 2024 is to have a drone with a video cam on it, fly it way up in the sky, like 4-5000 feet up, and record the shadow of the sun crossing the surface of the earth.

EDIT, I mean shadow of the moon crossing the surface of the earth
 
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oldbadger

Skanky Old Mongrel!
I think you mean, I have corrected you in what is a point.
Ummmm..... No.
It seems that you cannot grasp the idea that as this Universe, which is unbounded, expands, that it EITHER expands the space within itself (thus causing 'fixed' points to move away from each other with the expansion), OR creates new space with infinite new points.......... this second aspect which you reject, thus leaving you tied to the former, in which case your points do move.
 

Kangaroo Feathers

Yea, it is written in the Book of Cyril...
It demonstrates that space cannot be displaced, it is the static /stationary reference frame. I gave you a box , XYZ , the box although empty contains elements, remove all these elements and what are you left with?
You are misusing "static" again, and apparently unfamiliar with virtual particles, the existence of which has been proven by Hawking radiation. I see how you were, in fact, trying to answer my question, but you seem to lack the foundational concepts to understand it. May I recommend "A Brief History of Time" as a good starting point? Dr Brian Cox also tackles some of this stuff in a relatively easy to understand manner, so you might like to look up some of his documentaries if you're interested in learning more.
 
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