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Seeing things in their past? You are full of beans!

J

james blunt

Well-Known Member
Darkstorn said:
No need to apologize: After all, it was directed at you.



We could try with this simple equation: How long would it take for my tear to fall to the ground assuming a distance of 10 centimeters from the floor and a speed of 1 meter per second?
Click to expand...
You must be lying in some strange position lol.

So let us look at your basic equation of a free falling tear under the gravitational force of the Earth.

a = 9.82m/s2

10 cm is 1/10th of a metre

So we can calculate 1/10th of 9.82m/s

Which is 9.82/10 = 0.982 m/s

Did I guess correctly?



 
D

Darkstorn

This shows how unique i am.
Sustainer said:
You must be lying in some strange position lol.
Click to expand...

Hm. Lol indeed.

(I was implying that i was lying on the floor, laughing.)

So let us look at your basic equation of a free falling tear under the gravitational force of the Earth.

a = 9.82m/s2

10 cm is 1/10th of a metre

So we can calculate 1/10th of 9.82m/s

Which is 9.82/10 = 0.982 m/s

Did I guess correctly?
Click to expand...

Well, it's not about guessing, but no. The time it takes for my tear to fall to the ground is not 0.982 m/s. In fact, the actual speed of the tear in this example would be 1 m/s.
 
D

Darkstorn

This shows how unique i am.
Sustainer said:
No it wouldn't.
Click to expand...

"assuming a distance of 10 centimeters from the floor and a speed of 1 meter per second"

I gave you the speed in the equation itself. You can't just arbitrarily change it.

Your 1m/s is 0.982m/s , that is the result of the gravity constant acceleration.
Click to expand...

No, the 1m/s is already adjusted for that. I gave you the actual speed. And i didn't give you earth as a reference point.
 
Subduction Zone

Subduction Zone

Veteran Member
Sustainer said:
You must be lying in some strange position lol.

So let us look at your basic equation of a free falling tear under the gravitational force of the Earth.

a = 9.82m/s2

10 cm is 1/10th of a metre

So we can calculate 1/10th of 9.82m/s

Which is 9.82/10 = 0.982 m/s

Did I guess correctly?
Click to expand...

No.
 
J

james blunt

Well-Known Member
Darkstorn said:
"assuming a distance of 10 centimeters from the floor and a speed of 1 meter per second"

I gave you the speed in the equation itself. You can't just arbitrarily change it.



No, the 1m/s is already adjusted for that. I gave you the actual speed. And i didn't give you earth as a reference point.
Click to expand...
So where are you finding the extra applied acceleration from?

My answer corrects your error .
 
D

Darkstorn

This shows how unique i am.
Sustainer said:
So where are you finding the extra applied acceleration from?

My answer corrects your error .
Click to expand...

Rofl. Firstly: I wasn't giving you a physics question there, strictly a math one. I didn't give you enough reference points to imply anything but.

Second: I'm talking about my tears. They have been calculated moving at exactly 1 meter per second in the Martian atmosphere.

Since you want it to be about physics; Assume Mars as reference point, and assume an already adjusted for, exact 1 m/s velocity. Try again now.

/E: None of this even begins to make up for the fact that you answered my question on how long it would take, with a velocity.
 
J

james blunt

Well-Known Member
Darkstorn said:
Second: I'm talking about my tears. They have been calculated moving at exactly 1 meter per second in the Martian atmosphere.

Since you want it to be about physics; Assume Mars as reference point, and assume an already adjusted for, exact 1 m/s velocity. Try again now.
Click to expand...
How long would it take for my tear to fall to the ground on Mars assuming a distance of 10 centimetres from the floor and a gravitational constant of a speed of 1 meter per second?

Now I have read your question correctly you have got to be kidding right ?

1/10th of a second obviously

added- or precisely 919263177 Hz Earth time.
 
D

Darkstorn

This shows how unique i am.
Sustainer said:
What you mean well duh?

I gave the answer didn't I ?
Click to expand...

Yeah but i think the message was lost.

/E: On you. I mean the message was lost on you. But now it doesn't really matter. For a moment i thought this was going to be funny but at this moment i realize only sadness will ensue.
 
J

james blunt

Well-Known Member
Subduction Zone said:
Wrong, you used the wrong equation for even your changed example. The instantaneous speed of an object in freefall that began with a velocity of zero is √(2dg). Putting in .1 m and 9.8 m/s^2 into the equation you get roughly 1.4 m/s.
Click to expand...
Its an acceleration not a speed. I worked it out on a speed constant like the question asked. The instantaneous acceleration of an object on earth in free fall is a=9.82m/s2
 
Subduction Zone

Subduction Zone

Veteran Member
Darkstorn said:
Yeah but i think the message was lost.

/E: On you. I mean the message was lost on you. But now it doesn't really matter. For a moment i thought this was going to be funny but at this moment i realize only sadness will ensue.
Click to expand...
Things that he should have learned in 9th grade.
 
Subduction Zone

Subduction Zone

Veteran Member
Sustainer said:
Its an acceleration not a speed. I worked it out on a speed constant like the question asked. The instantaneous acceleration of an object on earth in free fall is 9.82m/s2
Click to expand...
You still have no clue. The acceleration is constant.

Things you should have learned in 9th grade.

Why aren't you trying to learn now?
 
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