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Seeing things in their past? You are full of beans!

Polymath257

Think & Care
Staff member
Premium Member
<--- continued from above -->

Now, let's take the pen beside you that is 5 1/2" long in *your* reference frame and the pen on the spacecraft going past you at 86% of c which is 5 1/2" long in *its* reference frame (that of the spacecraft). Each is measured to be 2 3/4" long in the other reference frame.

Now introduce a *second* spaceship that goes past you at 86% of the speed of light, but in the opposite direction as the first. And yes, it also has a pen that is moving along with it and is measured to be 5 1/2" long in the frame of the second spacecraft. So far, not much changes. You see the pen on the second spacecraft as being 2 3/4" long. The second spacecraft sees your pen as 2 3/4" long. Not much different than with the first spacecraft.

But, what does the first spacecraft see concerning the second? This is where things start getting more strange. We first have to ask how fast the second spacecraft is moving in the frame of the first: how fast do they see each other passing by? Now, you might suspect it is 86% + 86% =172% of c. But this isn't possible! NOTHING MOVES FASTER THAN c in any frame. The actual speed they see the other moving past is (.86+.86)/(1+.86*.86) = .9887 c!

Now, in the frame of the first ship, the pen on the *second* ship will be measured to be 5.5*sqrt(1-(.9887)^2 ) = .82". Similarly, the pen on the first will be measured to be .82" from the second ship.

So, which of these lengths is 'correct'? ALL of them are. They can all be used *in the appropriate frame* to do any calculation required to do physics, chemistry, etc. Now, it makes sense in this case to work with the length of the pen in the frame where the pen is at rest (so, from the respective spacecraft where the pens are). But there is NOTHING that is required about that. And, in fact, it is often easier to do calculations from some frames rather than others, depending on the problem. They are all equivalent!

Next, we can go one step up on the strangeness factor.Let's look at clocks. Suppose you have an atomic clock calibrated to give accurate time. On each of the spacecraft, there are also similarly calibrated atomic clocks. These are all clocks that are as accurate as we can get them and are all calibrated to measure via the definition of a second that is typically used. So, let's suppose, for the sake of this example, that you time some process as taking exactly 10 seconds in your frame.

Now, the first spacecraft going past you watches and times this same process with its atomic clock. it measures that same process as taking 20 seconds. Your atomic clock appears to be going slow according to the atomic clock on the spacecraft! The same is true for the second spacecraft going past in the other direction at 86% of c. Both spacecraft see that process as taking 20 seconds and not 10 seconds. This is known as time dilation.

But, now, let's have some process happen on the first spacecraft. A careful measurement is done on that spacecraft and that process is measured to take 10 seconds in the frame of the first spacecraft. What do you see? You might think you would measure it to be 5 seconds, but what you would really measure is that this process would take 20 seconds! Again, the situation is symmetric. Each of you sees the clocks of the other as being slower.

Now, finally, we ask the second spacecraft what it sees of the process that takes 10 seconds on the first. Now, recall that the two spacecraft see each other going past at 98.87% of c. It turns out that the 10 seconds on the first spacecraft will be measured to take 66.8 seconds from the second spacecraft! So, the process that took 10 seconds as measured by the first spacecraft will take 20 seconds as measured by your atomic clocks and will take 66.8 seconds as measured by the atomic clocks on the second spacecraft.

In this, we have had three frames of reference: yours, and two from the two spacecraft. The two spacecraft are going at 86% of the speed of light past you in your frame. Because they are in different frames, they measure different lengths and different time durations. Length and time are relative to the frame of reference. They are NOT absolute. Furthermore, there is not one frame that 'gets it right'. All the frames give equivalent, but different descriptions of what is going on.
 

Polymath257

Think & Care
Staff member
Premium Member
Yes but that pen is actually 5 1/2" long, it doesn't matter whether they say it is 2 3/4" long in the other frame of reference.

One is the truth of the matter, and the other is a perceived truth.

Wrong. The length of the pen depends on the frame in which it is measured. In all cases, it was *physically measured*. The spacecraft brought out its ruler as it was passing by and measured right when the rule and the pen were lined up.
 
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Polymath257

Think & Care
Staff member
Premium Member
To me any physical distance in space between planets, or a star and a planet has an actual real distance.

Only as measured in some reference frame. The distance will be different in other frames. No frame is any better than another is measuring that distance.

Now, it is common if the planets are at rest with respect to each other (or nearly so---speeds need to be close to c for relativistic effects to be significant) to use the frame where they are at rest. But this is simply a simplifying method and is not at all required.

I also want to emphasize: these are effects that have been observed and verified. They are NOT simply theoretical.
 

Polymath257

Think & Care
Staff member
Premium Member
To me any physical distance in space between planets, or a star and a planet has an actual real distance.

Yes, you think distance is absolute. That was what everyone thought until a about 113 years ago. Since almost every speed you ever have to deal with is much, much smaller than c, the relativistic effects are so small that they don't matter. It is only if you get to speeds close to c where these become significant.

These differences are NOT just matters of perception. Each frame is a way of measuring distances and times and all frames are completely equivalent in their powers to do so.
 

Thermos aquaticus

Well-Known Member
NOTE: I see that @Polymath257 already explained a similar experiment and I didn't see it until after I posted mine. My post is a bit of a repeat, but hopefully they will both help you understand the concept.

Let me give you an example of why I ask this.

Let's say I lay a pen I have measured to be 5 1/2" on the table. It measures 5 1/2" long from that reference.

I walk away 10 feet, and look at it from that reference. It measures 1" long from that reference.

If you are standing still 10 feet away from the pen you are both in the same reference frame. What you are ultimately measuring in your example is the size of the image on your retina. You are not measuring the length of the actual pen.

For relativity, we are talking about something very different. Let's use your experimental set up and see what happens.

You have a camera and a pen that you lay sideways ten feet away. You take a picture and measure the length of the pen in the captured image using pixels as your measure. When the pen is ten feet away and is not moving relative to the camera it is 1,000 pixels across in the image. Now, let's put that pen on a superfast rocket, have it loop around the solar system, and then by the camera at a distance of 10 feet away at 0.86 times the speed of light. We snap a photo of that pen as it passes the camera at a position of 10 feet using the same camera settings as before. We measure the length of the pen again. This time it measure 500 pixels across (if my math is right, hopefully @Polymath257 checks it).

Next, we have the camera on an identical rocket, and have the two rockets flying parallel to one another just ten feet apart, and we also have them going 0.89 times the speed of light. On one rocket we have the camera, and on the other rocket we have the pen. We take another picture, just as before, and the pen is 1,000 pixels across once again.

So why do we get these different results depending on the relative motion of the pen to the camera? It is due to length contraction as a part of relativity. Which measurement of the pen is correct? All of them are correct.
 

TrueBeliever37

Well-Known Member
Wrong. The length of the pen depends on the frame in which it is measured. In all cases, it was *physically measured*. The spacecraft brought out its ruler as it was passing by and measured right when the rule and the pen were lined up.

But it wasn't physically handled and measured in a still position. I know which method is more accurate.

If I hold something out my car window at 70 mph and you go by at 120 mph, you are going to have a hard time measuring it accurately.
 
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TrueBeliever37

Well-Known Member
Yes, you think distance is absolute. That was what everyone thought until a about 113 years ago. Since almost every speed you ever have to deal with is much, much smaller than c, the relativistic effects are so small that they don't matter. It is only if you get to speeds close to c where these become significant.

These differences are NOT just matters of perception. Each frame is a way of measuring distances and times and all frames are completely equivalent in their powers to do so.

Light is at the speed of C when traveling from the sun to here. The formula Speed of light = C = distance/time works for covering that actual physical distance. C is a constant. That same formula should work for figuring how long it takes to get from a star to a planet if we truly know the physical distance between them.
 

Subduction Zone

Veteran Member
But it wasn't physically handled and measured in a still position. I know which method is more accurate.

This is a demand that you measure only objects with a zero velocity in your own frame of reference. Worse yet it means that you can't even do that very well since you cannot measure distant objects. For example you could not measure the house across the street from your house if the neighbor has a "No Trespassing" sign up. Nor could you measure the length of a car driving on the street for that matter.
 

Subduction Zone

Veteran Member
Light is at the speed of C when traveling from the sun to here. The formula Speed of light = C = distance/time works for covering that actual physical distance. C is a constant. That same formula should work for figuring how long it takes to get from a star to a planet if we truly know the physical distance between them.

No, light is at the speed of light for any frame of reference except for one moving at the speed of light.


Also here is something that you do not seem to understand. Let's say that you are in space. To you, your velocity appears to be zero. You pick out a star and by measuring its light spectrum you realize that it is stationary in regards to you too. If you measured the light from that star you would find that it is moving at c relative to you away from that star. Now a space ship passes you at half the speed of light moving towards that star. If it measured the speed of light from that star relative to him he would not measure the light as moving at 1.5 c, it would be moving a c relative to him. Now another spaceship passes you. It is moving at c directly away from that star. It does not measure the light from that star that is passing him as moving at .5 c. He measures it passing him at c.

The math behind the Lorentz transformations explains why those different people moving at different velocities all can measure the speed of the same light as going at c to all of them.
 

TrueBeliever37

Well-Known Member
NOTE: I see that @Polymath257 already explained a similar experiment and I didn't see it until after I posted mine. My post is a bit of a repeat, but hopefully they will both help you understand the concept.



If you are standing still 10 feet away from the pen you are both in the same reference frame. What you are ultimately measuring in your example is the size of the image on your retina. You are not measuring the length of the actual pen.

For relativity, we are talking about something very different. Let's use your experimental set up and see what happens.

You have a camera and a pen that you lay sideways ten feet away. You take a picture and measure the length of the pen in the captured image using pixels as your measure. When the pen is ten feet away and is not moving relative to the camera it is 1,000 pixels across in the image. Now, let's put that pen on a superfast rocket, have it loop around the solar system, and then by the camera at a distance of 10 feet away at 0.86 times the speed of light. We snap a photo of that pen as it passes the camera at a position of 10 feet using the same camera settings as before. We measure the length of the pen again. This time it measure 500 pixels across (if my math is right, hopefully @Polymath257 checks it).

Next, we have the camera on an identical rocket, and have the two rockets flying parallel to one another just ten feet apart, and we also have them going 0.89 times the speed of light. On one rocket we have the camera, and on the other rocket we have the pen. We take another picture, just as before, and the pen is 1,000 pixels across once again.

So why do we get these different results depending on the relative motion of the pen to the camera? It is due to length contraction as a part of relativity. Which measurement of the pen is correct? All of them are correct.

You may get different measurements, but they are not the accurate/real/true physical measurement.
 

Polymath257

Think & Care
Staff member
Premium Member
But it wasn't physically handled and measured in a still position. I know which method is more accurate.

If I hold something out my car window at 70 mph and you go by at 120 mph, you are going to have a hard time measuring it accurately.

It isn't a question of accuracy here. It isn't a question of the difficulty of the measurements. It is an issue of what the *correct* measurements in each frame would give.

If I had really, really good equipment, I could measure the length of a pen in your car as I am going by in another car. It is trickier, yes, but not impossible.

And, for 'slow' speeds like 120 mph, the length I measure for the pen would agree with the length *you* measure for the pen. If you have a 6" pen, then I will measure it to be 6" as I go by unless I have an incredibly accurate measuring devide that can detect relativistic effects at these speeds.

Another aspect: what I said about the measured lengths of the pens applies if the pens are aligned with the direction of travel. If, instead, they are aligned perpendicular to the direction of travel, everyone agrees that the pens are 5 1/2" long (in your original example).
 

Polymath257

Think & Care
Staff member
Premium Member
You may get different measurements, but they are not the accurate/real/true physical measurement.

Who says? They are the accurate, correct measurements *for that reference frame*. The *physical* length of the pen depends on the relative speed of the pen and the measuring device.
 

Subduction Zone

Veteran Member
You may get different measurements, but they are not the accurate/real/true physical measurement.

There is no "accurate/real/true physical measurement".

You will not learn if you keep demanding that your errors are correct and refuse to learn why scientists knew that simple Newtonian mechanics was wrong over 100 years ago.
 

Polymath257

Think & Care
Staff member
Premium Member
Light is at the speed of C when traveling from the sun to here. The formula Speed of light = C = distance/time works for covering that actual physical distance. C is a constant. That same formula should work for figuring how long it takes to get from a star to a planet if we truly know the physical distance between them.

Agreed. And in every reference frame, the measured speed of light will be the same value.

Again, this alone is very counter-intuitive. Suppose you are on a highway going at 50 mph. Suppose I go by you and am going at 120 mph. What is our *relative* speed? How fast am I pulling away from you? I hope it is clear that I am going at 70 mph in your reference frame. Do you see this? I am pulling away from you at 70 mph...ok?

But, at speeds close to c, the simple minded formula (subtraction) no longer works.

If I am going past you at 50% of c and turn on a light, I see that light pulling away from me at c, NOT 50% of c. You also see that light pulling away from you at c. Even someone going at 98% of c will see the light pulling away from them at c.
 

Thermos aquaticus

Well-Known Member
Light is at the speed of C when traveling from the sun to here. The formula Speed of light = C = distance/time works for covering that actual physical distance. C is a constant. That same formula should work for figuring how long it takes to get from a star to a planet if we truly know the physical distance between them.

What about a spaceship that is speeding away from the Sun at 0.5 c. How fast do you think the light from the Sun is travelling relative to the spaceship? Will people on the spaceship see light going by at 0.5 c, or at 1.0 c?
 

Polymath257

Think & Care
Staff member
Premium Member
This is a demand that you measure only objects with a zero velocity in your own frame of reference. Worse yet it means that you can't even do that very well since you cannot measure distant objects. For example you could not measure the house across the street from your house if the neighbor has a "No Trespassing" sign up. Nor could you measure the length of a car driving on the street for that matter.

And in a *valid* reference frame, you could, in fact, measure of those. We can (and do) use trigonometry to figure out how far away things are. This is how surveyors do it, after all.
 

TrueBeliever37

Well-Known Member
It isn't a question of accuracy here. It isn't a question of the difficulty of the measurements. It is an issue of what the *correct* measurements in each frame would give.

If I had really, really good equipment, I could measure the length of a pen in your car as I am going by in another car. It is trickier, yes, but not impossible.

And, for 'slow' speeds like 120 mph, the length I measure for the pen would agree with the length *you* measure for the pen. If you have a 6" pen, then I will measure it to be 6" as I go by unless I have an incredibly accurate measuring devide that can detect relativistic effects at these speeds.

Another aspect: what I said about the measured lengths of the pens applies if the pens are aligned with the direction of travel. If, instead, they are aligned perpendicular to the direction of travel, everyone agrees that the pens are 5 1/2" long (in your original example).

Still, when I ask how long it takes for a photon to get from a star to a planet, 30 million light years away. The same formula should work, that we use to determine how long the photon takes to get from the sun to this planet. What difference does it make about frame of reference? The photon is not in a ship, it is just traveling at the speed of light in both cases. The photon has the same frame of reference in both cases.
We have a constant speed of light in both cases , and an actual physical distance.
 

Subduction Zone

Veteran Member
Still, when I ask how long it takes for a photon to get from a star to a planet, 30 million light years away. The same formula should work, that we use to determine how long the photon takes to get from the sun to this planet. What difference does it make about frame of reference? The photon is not in a ship, it is just traveling at the speed of light in both cases.
We have a constant speed of light in both cases , and an actual physical distance.


Different observers would get different times. None of them are "correct". If you measured how long it takes for a photon to get from the Sun to Mars you would have a slightly different answer than the person that was on Mars that made the same measurement. Which one is "correct"?
 
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