@ArtieE @Kirran @Mestemia @gnostic
@Guy Threepwood
@Kirran
Quantifying the absence of Natural Selection.
A common criticism from some creationists here is that evolution through natural selection is a just-so story without there being any way to detect whether it is happening or not. This is not the case. There are many objective and mathematical ways to detect whether a specific gene or a group of genes is under natural selection or not.
I will present a simple example to show this. Consider a gene that has two variants (alleles) a and b. Then a population of creatures can have the variants aa, ab or bb. If N be the total number of creatures in the entire population and N(aa), N(bb) and N(ab) are numbers possessing the various variants then :-
Fraction of the population with gene-type aa is f(aa) = N(aa)/N
Fraction of the population with gene-type ab is f(ab) = N(ab)/N
Fraction of the population with gene-type bb is f(bb) = N(bb)/N
One can evaluate this by statistical sampling in an animal population for example.
Since all creatures have a pair of chromosomes, there are two positions for every gene, one from the father and one from the mother. So, gene a occupies both positions in individual of type aa; occupies one position in individuals of type ab; and is absent in individuals of type bb.
Thus frequency of occurrence of gene variant a of the gene in the population is
g(a) = [2N(aa)+N(ab)] /2N = f(aa) + 0.5f(ab)
Similarly frequency of occurrence of gene variant b of the gene
g(b) = [2N(bb)+N(ab)]/2N = f(bb) + 0.5f(ab)
So far so good. But now of we assume that selection is absent. Thus:-
i) Mating preference is unrelated to the gene variants . That means no sexual selection effect exists on the genes and mate choice is random with respect to this gene variants a and b
ii) All variants (aa, ab, bb) have the same fertility potential and produce on average the same number of babies.
iii) These gene variants have no effect on the rate of survival of the babies into adulthood. Thus Natural Selection is not operating on these gene variants.
Then it can be mathematically proved that:-
1) Gene frequencies and populations fractions are constant from generation to generation.
2) They obey the equilibrium relation:-
f(aa) = g(a)*g(a)
f(ab) = 2g(a)*g(b)
f(bb) = g(b)*g(b)
These will be the population fractions and gene frequency relations if natural selection is not operating on a gene. While most genes show selection effects, there are some whose variants are neutral and they (like the blood group type MN variants) do show this equilibrium relation in the populace.
These relations can be extended to genes that have three or more variants as well.
Conclusion:-
1) It is not the case that we have no clue as to determine when natural selection is operating and when it is not. The distribution of gene variants in case of general absence of selection (no sexual selection and equal fertility, equal survivability to adulthood) can be determined mathematically and genes have been identified that satisfy these neutral under evolution criteria.
2) But many genes do not follow the equilibrium relations and how much and the manner of the deviation tells the scientists which process of evolution is acting on the gene.
Poor old Hardy and Weinberg not being credited!
I really enjoyed this stuff when I was learning about it at uni, it's nice to be reminded of it.